question about electronic circuits?
In a circuit there is a 100 volt DC source, a 2 ohm
resistor in parallel with a 4 ohm resistor, and then those
resistors are in series with a 3 ohm resistor in parallel
with a 6 ohm resistor. The circuit is terminated in a load
whose value varies randomly between 10 and 20 ohms.
If the power dissipated in the 2 ohm resistor goes above 35
watts, the resistor will burn and its resistance will jump
from 2 ohms to 1000000 ohms.
Solve the circuit 100,000 times (using random values for the
load). During the 100,000 simulations, count the number of times that
the 2 ohm resistor burns up. Also, calculate the average
voltage delivered to the load resistor when the 2 ohm
resistor has burned up.
Your program should output only two numbers on separate lines
as follows:
1-Number of times that the 2 ohm resistor burns
2-Average voltage delivered to the load resistor calculated
over the cases where the 2 ohm resistor has burned up
The seed to use for the random number generator is 100000
I have no problem with the programming stuff, just the actual calculations.
Tagged with: load resistor • ohm resistor • ohms • random number generator • random values • resistance • resistors • simulations • volt dc source • watts
Filed under: Parallel Electronic Circuits
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The expression of the power dissipated in the 2 ohms resistor is P = 0.5 * ( (4/3) * 100/ ( (10/3) + x) )² where x is the value of the load. In fact, the 2 ohm resistor will burn every time the load resistor's value is under 12.60304812 ohms.
The expression of the voltage delivered to the load resistor when the 2 ohms resistor has burned up is V = ( 100 * x ) / (6 + x) where x is the value of the load.
I've avoided to put all the calculations here, if you need them or need assistance on the programming stuff, feel free to send me an email. I hope this information helps you to get your program done ^^.